Chemistry, asked by nazerpp52, 1 month ago

at constant pressure a gas molecule has a volume of 400L at a temperature of 300 K. what will be the volume of gas when temperature is doubled​

Answers

Answered by VishnuPriya2801
123

Answer:-

Given:-

Initial volume of the gas (V₁) = 400 L

Initial Temperature of the gas(T₁) = 300° K

Also,

Final Temperature of the gas is doubled.

So, Final Temperature (T₂) = 2 * 300 = 600° K.

We know that,

Charle's law states that, at constant pressure the volume of a gas is directly proportional to the temperature.

⟹ V ∝ T

⟹ V = kT (k = constant)

⟹ V/T = k

⟹ V₁/T₁ = V₂/T₂

Let the final volume of the gas be V₂.

Substituting the values in the above equation we get,

⟹ 400/300 = V₂/600

⟹ (400/300) * 600 = V₂

⟹ 800 L = V₂

The volume of the gas becomes 800 L when the temperature is doubled.

Answered by Anonymous
106

Answer:

 \large \dag Question :-

At constant Pressure a gas molecule has a volume of 400 L at a temperature of 300K .What will be the volume of gas when temperature is doubled .

 \large \dag Answer :-

\small\text{The volume of gas when temperature is doubled is 800 L.}

 \large \dag Solutions :-

\small\text{•Hey mate ,first let verify your question.Then start our calculations}

\small\text{•In the question given that,}

\small\text{■At constant Pressure a gas molecules has a volume of 400 L at a temperature of 300K .}

\small\text{■Here we are going to find what will be the volume of gas when temperature is doubled}

\small\text{■Here we know initial temperature of gas  value but we dont know the final temperature of gas value so }

\small\text{■Final temperature =2×300=600degree Celcius}

Here we come yo an understanding that we should use Charles law formula to get the answer to this question.

first let us know what Charles law states.

It states that ,At the constant Pressure the volume of gas is directly proportional to the temperature of that gas

Here he also given ,V is proportional to T

\small\text{♧V=kT (where K is constant)}

\small\text{♧V/T=K}

\small\text{☆Here Charles gave a formula in which in his law gave ,That is}

\small\text{♧V1/T1=V2/T2}

Therefore,

\small\text{☆Now substituting all the values we get that }

\small\text{▪400/300=V2/600}

\small\text{▪400×600/300=V2 =800L }

 \large \dag Hope it helps u mate .

 \large \dag Thank you .

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