At constant pressure, calculate the root mean square velocity at temperature 27 °C if its rms speed at 0°C is 4km/s
Answers
Answered by
11
Hey dear,
◆ Answer -
(vrms)2 = 4.193 km/s
◆ Explanation -
# Given-
T1 = 0 °C = 273 K
T2 = 27 °C = 300 K
(vrms)1 = 4 km/s
# Solution-
RMS velocity is given by -
vrms = √(3kT/2)
Therefore,
(vrms)1 / (vrms)2 = √(T1/T2)
(vrms)2 = (vrms)1 × √(T2/T1)
(vrms)2 = 4 × √(300/273)
(vrms)2 = 4.193 km/s
Therefore, RMS velocity of gas at 27 °C is 4.193 km/s.
Hope this helps you...
◆ Answer -
(vrms)2 = 4.193 km/s
◆ Explanation -
# Given-
T1 = 0 °C = 273 K
T2 = 27 °C = 300 K
(vrms)1 = 4 km/s
# Solution-
RMS velocity is given by -
vrms = √(3kT/2)
Therefore,
(vrms)1 / (vrms)2 = √(T1/T2)
(vrms)2 = (vrms)1 × √(T2/T1)
(vrms)2 = 4 × √(300/273)
(vrms)2 = 4.193 km/s
Therefore, RMS velocity of gas at 27 °C is 4.193 km/s.
Hope this helps you...
Similar questions
English,
7 months ago
Social Sciences,
7 months ago
Chemistry,
7 months ago
Biology,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago