Question

At constant pressure calculate the root mean square velocity of a gas molecule

Answer 1

Gadakhsanket Virtuoso

Hey dear,

◆ Answer -

(vrms)2 = 4.193 km/s

◆ Explanation -

# Given-

T1 = 0 °C = 273 K

T2 = 27 °C = 300 K

(vrms)1 = 4 km/s

# Solution-

RMS velocity is given by -

vrms = √(3kT/2)

Therefore,

(vrms)1 / (vrms)2 = √(T1/T2)

(vrms)2 = (vrms)1 × √(T2/T1)

(vrms)2 = 4 × √(300/273)

(vrms)2 = 4.193 km/s

Therefore, RMS velocity of gas at 27 °C is 4.193 km/s. ❤❤❤♥♥♥♥❤❤❤❤♥♥

Answer 2

Explanation:

• As we think about that , it is the pressure that helps us to calculate the square velocity of as gas molecule. It is known that the absolute temperature of the gas is increased by 3 times that will know about the temperature in an increasingly way in its root means square velocity of the gas molecules