Question

at constant pressure the volume of a definite mass of any gas is 360 ml. the gas is kept at 15°c. find the temperature at which the volume of the gas will be 480 ml​

Answer 1

Explanation:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ at \: constant \: pressure: \\ V_1 = 360 \: ml = \frac{360}{1000} \: l = 0.36 \: l \\ V_2 = 480 \: ml = \frac{480}{1000} \: l = 0.48 \: l \\ T_1 = 15°C = 15 + 273 = 288 \: K\\ \\ \frac{V_1}{T_1} = \frac{V_2}{T_2} \\ T_2 = \frac{V_2 \times T_1}{V_1} \\ T_2=\frac{0.48 \times 288}{0.36} \\ \blue {\boxed{T_2 = 384 \: K}} \\ \\\red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$