Question

At constant temperature 80% AB dissociates into A2 and B2, then the equilibrium constant for
2AB (g) = A2(g) + B2(g) is
1) 1
2) 0.25
3) 16
4) 4
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Answer 1

Answer: 4

Explanation:

Answer 2

The equilibrium constant for the given reaction is equal to 4.

• If we take the initial concentration of AB to be equal to C, on 80% dissociation the concentration of AB is equal to 0.2C while the concentration of A2 and B2 is equal to 0.4C each.
• The equilibrium constant of a reaction is equal to the ratio of the concentration of the products to that of reactant raised to their stoichiometric constants.
• Hence, equilibrium constant is equal to [A2].[B2]/[AB]² = 4.