at constant temperature a gas at minus 23 degree celsius is heated to 127 degree Celsius calculate the percentage increase in the volume of the gas
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At constant pressure
V ∝ T
T1 = -23°C = -23 + 273 = 250 K
T2 = 127 °C = 127 °C + 273 = 400 K
V2 / V1 = T2 / T1
(V2 / V1) - 1 = (T2 / T1) - 1
ΔV / V1 = ΔT / T1
ΔV = V1 × ΔT / T1
ΔV = V1 × (400 - 250) / 250
ΔV = 0.6 V1
Percentage increase in volume = 0.6 × 100 = 60%
V ∝ T
T1 = -23°C = -23 + 273 = 250 K
T2 = 127 °C = 127 °C + 273 = 400 K
V2 / V1 = T2 / T1
(V2 / V1) - 1 = (T2 / T1) - 1
ΔV / V1 = ΔT / T1
ΔV = V1 × ΔT / T1
ΔV = V1 × (400 - 250) / 250
ΔV = 0.6 V1
Percentage increase in volume = 0.6 × 100 = 60%
kiranmahapatra4:
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hey mate ....
here's your answer ...
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