Question

at constant temperature a gas is at a pressure of 1080 mm Hg.If the volume is decreased by 40%,find the new pressure of the gas

Answer 1

Given

Process=> constant temperature

So

Pv=nrt


Nrt= constant

P1v1= P2v2-------(1)

Data Given
Volume decrease by 40%
Let initial volume =v1

Final volume = 0.6v1

Pressure (p1) =1080 mm of hg

Putting the values in equation 1, we get

1080xv= p2x0. 6v1

$p2 = \frac{1080 \times v1}{0.6v1}$


$p2 = \frac{1080}{0.6}$

Final pressure (p2) =1800 mm of hg


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Answer 2

Given

P1=1080 mm Hg

P2=?

Let V1 = x

40% of x
=40×x/100 =2x/5

the new volume
= x-2x/5
=5x-2x/5
=3x/5
=0.6x


By Boyle's Law

P1V1=P2V2

1080×x=P2 × 0.6x

P2=1800 mm Hg

P2=1080×x/0.6x