Question

At constant temperature and pressure 2L volume of dinitrogen gas reacts with 6l volume of dihydrogen gas then how many liters of ammonia gas will produce?​

Answer 1

Given: At constant temperature and pressure 2L volume of dinitrogen gas reacts with 6l volume of dihydrogen gas.

To find: We have to find the amount of ammonia produced.

Solution:

The reaction between nitrogen gas and hydrogen gas is-

$N_2+3H_2\rightarrow 2NH_3$

So, 1 liter volume of nitrogen gas reacts with 3 liters volume of hydrogen gas to form 2 liters volume of ammonia gas.

Thus 2 liters volume of nitrogen gas reacts with 6 liters volume of hydrogen gas to produce 4 liters volume of ammonia gas.

Thus 4 liters of ammonia gas will produce.

Answer 2

Given:

2L of the volume of dinitrogen gas reacts with 6L volume of dihydrogen gas at a constant temperature and pressure.

To Find:

The Volume of ammonia produced in liters.

Solution:

The given problem can be solved by using Mole Concept.

Chemical Reaction:

• N2 (gas) + 3H2 (gas)  ----> 2 NH3 (gas).

• For 1 mole of dinitrogen and 3 moles of dihydrogen, 2 moles of ammonia is produced.
• For 2 moles of dinitrogen and 6 moles of dihydrogen, four moles of ammonia are produced. ( From the properties of the mole concept.)

Consider a Chemical reaction x A + y B ---> zC.

• x moles of A and y moles of B are reacted together to form z moles of C.
• Similarly, if 2x moles of A and 2y moles of B are reacted, we get 2z moles of the compound C.

Considering the above-mentioned points:

• 1 L volume of dinitrogen gas reacts with 3 L volume of dinitrogen to produce 2 L volume of ammonia. ( As per chemical reaction) .
• As the volume of the reactants is doubled, hence the volume of the product also gets doubled.
• Therefore, 4 Liters of ammonia will be produced.

Therefore, 4 liters of ammonia gas will be produced when it is reacted with 2 liters of dinitrogen gas and 6 liters of dihydrogen gas.