Question

at constant temperature and volume is decomposed out of 2 atm of oxone taken initially and the equilibrium 2O3=3O2is established, Kp for the decomposition of ozone is​

Answer 1

Answer:

at constant temperature and volume is decomposed out of 2 atm of oxone taken initially and the equilibrium 2O3=3O2is established, Kp for the decomposition of ozone is

Answer 2

Answer:

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Explanation:

let the volume of ozone in the mixture is x ml , therefore volume of oxygen in the mixture is 20 - x ml 

now decomposition of ozone can be represented by  2O3 ---> 3O2

3 x 22400 ml of O2  is formed from 2 x 22400 ml 0f O3

 therefore x ml of O3 will give 2/3 x ml of O2 , now 

 x + (20 - x) + 2/3x = 21 , on solving we get 

x = 3/2ml = 1.5 ml 

therefore % age of ozone in the mix = 1.5 / 20   x  100 = 7.5% by volume