At constant temperature if pressure increases by 1% the percentage decrease in volume is
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Let the pressure be denoted by 'p' if the pressure increased by 1% then
p¹ + p¹/100 =p
P=101p¹/100
By boyles law
PV= constant
P¹V¹ =PV
P¹v¹ = 101p¹/100×v
If we cancel p¹on both sides
V¹ =101/100×V
V=100V¹/101
S if pressure increased by 1% volume decrease by 100/101 of its initial volume.
Hope my answer helps you. Please mark me as Brainliest.
p¹ + p¹/100 =p
P=101p¹/100
By boyles law
PV= constant
P¹V¹ =PV
P¹v¹ = 101p¹/100×v
If we cancel p¹on both sides
V¹ =101/100×V
V=100V¹/101
S if pressure increased by 1% volume decrease by 100/101 of its initial volume.
Hope my answer helps you. Please mark me as Brainliest.
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