Question

At constant temperature, when the volume of a
gas is reduced to (1/3)rd, the pressure will increase
(a) 1 time
(c) 3 times
(b) 2 times
(d) 4 times​

Answer 1

Answer:

3 times

Explanation:

the decrease in volume is 1/3

v is inversley proportional to p

so that pressure will increase to 3 times

Answer 2

Answer:

Explanation:

The decrease in volume is $1/3$

$v$ is inversely proportional to $p$ (or) $(v\alpha \frac{1}{p})$

Hence the pressure will increase to 3 times.

Pressure definition:

"Pressure" is defined as the thrust (force) applied to a surface per area. The force to area ratio is another way to describe it (over which the force is acting).

Volume definition:

Volume is a three-dimensional measurement that's used to gauge a solid shape's capacity. It implies that the volume of a closed form determines how much space it can occupy in three dimensions.

Temperature definition:

Temperature is a unit used to represent hotness or coolness on any of a number of scales, including Fahrenheit and Celsius. According to temperature, heat energy will naturally move from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature).

Ideal gas law:

We can also assert that $(\frac{P*V}{T*n})$ is equivalent to a constant, much like the other gas laws. If the gas being described is thought of as ideal, the constant can be assessed.

The pressure, volume, temperature, and number of moles of an ideal gas are all related by a single equation known as the ideal gas law. The equation becomes: if we replace the constant with the variable $R$.

$(P*V/T*n)=R$

The multiplication signs are conveniently removed to make the ideal gas law appear as follows:

$PV=nRT$

The ideal gas constant,$R$, is the name of the variable in the equation.

At constant temperature, when the volume of a gas is reduced to $(1/3)$rd, the pressure will increase $3$ times.

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