Question

At constant volume, the specific heat of a gas is 0.025 cal K−1 g−1 and its molecular weight is 120 g mol−1. The atomicity of the gas is:
Given: R = 2 cal K−1mol−1
DiatomicTriatomicMonoatomicNone of the above​

Answer 1

Given,

Specific heats at constant P, (C

p

)=0.125cal/g

Specific heats at constant V, (C

v

)=0.075cal/g

(a) ∵C

p

−C

v

=

M

R

∴0.125−0.075=

M

2

or M=40

(b) For atomicity, γ=

C

v

C

p

=

0.075

0.125

=1.66

i.e., gas is monoatomic.

(c) Since gas is monoatomic and thus no. of atoms of gas in 1 mole,

=6.023×10

23

atoms

Answer 2

Thanks for your points sorry for my answer