At Deoprayag river Alaknanda mixes with the river Bhagirathi and becomes river Ganga. Suppose Alaknanda has a width of 12 m, Bhagirathi has a width of 8 m and Ganga has a width of 16 m. Assume that the depth of water is the same in the three rivers. Let the average speed of water in Alaknanda be 20 km/h and in Bhagirathi be 16 km/h. Find the average speed of the water in the river Ganga.
Answers
Let the Depth of each river be h km.
Now, In the Given case, the volume rate of the flow of water will be constant throughout.
This means, Volume rate of the River Alaknanada + Volume Rate of the River Bhagirathi = Volume Rate of the River Ganga.
[This is because, In series connection of Horizontal pipe (here stream of river) the sum of the volume rate equal to the final volume rate flow.]
Volume rate of flow of River Alaknanda = Area of cross section × Velocity of the water in River Alaknanda.
= 12/1000 × h × 20
Similarly,
Volume rate of flow of River Bhagirathi = Area of cross section × Velocity of the water in River Bhagirathi.
= 8/1000 × h × 16
Similarly, Volume rate of flow of River Ganga = Area of cross section × Velocity of the water in River Ganga.
= 16/1000 × h × Velocity
Now, Finally,
16/1000 × h × Velocity = 12/1000 × h × 20 + 8/1000 × h × 16
Cancelling h and 1000 from each side,
16 × Velocity = 12 × 20 + 8 × 16
On Solving, We get, Velocity = 23 km/hr.
Hence, the average velocity of the water in the river Ganga is 23 km/hr.
Hope it helps.
Let the Depth of each river be h km.
This means, Volume rate of the River Alaknanada + Volume Rate of the River Bhagirathi = Volume Rate of the River Ganga.
[This is because, In series connection of Horizontal pipe (here stream of river) the sum of the volume rate equal to the final volume rate flow.]
= 12/1000 × h × 20
Volume rate of flow of River Bhagirathi = Area of cross section × Velocity of the water in River Bhagirathi.
= 8/1000 × h × 16
= 16/1000 × h × Velocity
Now, Finally,
16/1000 × h × Velocity = 12/1000 × h × 20 + 8/1000 × h × 16
16 × Velocity = 12 × 20 + 8 × 16
On Solving, We get, Velocity = 23 km/hr.
Hope it helps.