Question

At equilibrium N2O4=2No2 the observed molecular weight of N2O4is 80g/mol at 350k .The Percentage dissociation of No2 at 350k is?

Answer 1

Answer:

At equilibrium N2O4(g)⇌2NO2(g)the observed molecular weight of N2O4is 80g mol−1 at 350 K. The percentage dissociation of N2O4(g) at 350 K is:

A .

10%

B .

15%

C .

20%

D.

25%

ANSWER

                  N2O4⇌2NO2

t=0,            1                0

t=teq       1−α           2α

Normal molecular mass of N2O4=92g/mol

Observed molecular mass= 80g/mol

∴ Van’t Hoff factor i =8092=1.15

⇒i=11−α+2α=Calculated colligative propertyObserved colligative property

⇒1.15=11+α

⇒α=0.15

∴ Percentage dissociation of N