Question

At equilibrium, PCL5 gives PCL3+ Cl2, the observed molecular weight of PCl5 is 124 g mol-¹ at 250°C. The degree of dissociation of PCl5 at 250°C will be?

Answer 1

Answer:

67%

Explanation:

Answer 2

The degree of dissociation of $PCl_5$at 250°C will be 0.6814.

Explanation:

$i=\frac{\text{Normal molecular mass}}{\text{Observed molecular mass}}$

Observed molecular mass of $PCl_5=124 g/mol$

Normal molecular mass of $PCl_5=208.5 g/molg/mol$

$i=\frac{208.5 g/mol}{124 g/mol}=1.68$

For dissociation the degree of dissociation is given by:

$\alpha =\frac{i-1}{n-1}$

For $PCl_5$ value of n =2

$\alpha =\frac{1.86-1}{2-1}=0.6814$

learn more about van't Hoff factor :

https://brainly.in/question/2021331

https://brainly.com/question/12957582