Question

At father is twice as old as his son. 20 year ago the age of father was 12 times of the son . the present age of the father is​

Answer 1

Answer:

let son age = x

father is twice as son= x+x = 2x

20 yrs old the father is 12 times of his son

20x+12

33

Answer 2

☯ Let present age of son be x

☯ Therefore, present age of father is 2x

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★ According to Question

20 year ago the age of father was 12 times of the son.

Therefore,

• Age of son 20 years ago = (x - 20)
• Age of his father 20 years ago = (2x - 20)

➯ 2x - 20 = 12(x - 20)

➯ 2x - 20 = 12x - 24

➯ 2x - 12x = - 240 + 20

➯ - 10x = - 220

➯ x = - 220/-10

➯ x = 22

Hence,

• Present age of son, x = 22 years

• Present age of father, 2x = 2 × 22 = 44 years

∴ Present age of father and his son is 44 years and 22 years respectively.