Question

@(Father old + son old)=49.
5 years before father age is 2 multiple from son.
Now how old father and son?​

Answer 1

✬ Son = 18 years ✬

✬ Father = 31 years ✬

Step-by-step explanation:

Given:

• Sum of father and son age is 49 years.
• 5 years ago father was 2 times of his son.

To Find:

• Present ages of son and father ?

Solution: Let father's age be x and son's age be y years. Therefore,

➼ (Father + Son) age = 49 years

➼ x + y = 49

➼ x = 49 – y.....(1)

[ 5 years before their ages ]

➨ Father's age = (x – 5) years

➨ Son's age = (y – 5) years

A/q

• 5 years ago father was 2 times of his son.

$\implies{\rm }$ (x – 5) = 2(y – 5)

$\implies{\rm }$ (49 – y – 5) = 2y – 10

$\implies{\rm }$ 44 – y = 2y – 10

$\implies{\rm }$ 44 + 10 = 2y + y

$\implies{\rm }$ 54 = 3y

$\implies{\rm }$ 54/3 = y

$\implies{\rm }$ 18 = y

So, Their present ages are

➫ Son's age is y = 18 years

➫ Father's age is (49 – y)

= (49 – 18) = 31 years

Answer 2

Given :

Sum of father's age and son's age = 49

5 years before father's age is 2 multiple from the son.

To Find :

Their Present Ages.

Solution :

Suppose father's age be x and son's age y.

Then,

x + y = 49 .....( i )

5 years ago :

• Father's age = ( x–5 )

• Son's Age = ( y–5 )

According to question :

2 ( y–5 ) = ( x–5 )

2y–10 = x–5

2y–x = 5

–x + 2y = 5 .....( ii )

Add ( i ) and ( ii ) :

3y = 54

y = 18

Putting The Value Of y in ( i )

x + 18 = 49

x = 31

Hence,

• Father's Age x = 31 years.

• Son's Age y = 18 years.

Verification :

Father's age + Son's age = 49

31 years + 18 years = 49 years.

Verified.

Hope it helps.

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