Math, asked by farazzabdul, 5 months ago


@ Find the equation of the circle passing through the points (2,1) (5,5), (-6,7)
Tahs: x2+y24x-12y+5=0)​

Answers

Answered by lalitnit
0

Answer:

 {x}^{2} + {y}^{2} +2gx+2f y+c=0

(2,1)

 {4} + {1} +4g+2f+c=0 \\ 4g+2f+c= - 5

(5,5)

25 + 25 + 10g + 10f+ c = 0 \\ 10g + 10f + c =  - 50

(-6,7)

36 + 49  - 12g + 14f+ c = 0 \\ - 12g + 14f + c =  - 85

On solving the three variable equations

We get,

g =  \frac{1}{2} \\ f =  - 6 \\ c = 5

So the equation of the circle

 {x}^{2}  +  {y}^{2}    + x - 12y + 5 = 0

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