Question

@ for any acute angle Q , prove that
(1)sin2Q +cos2Q=1
(2) 1+ tan2Q - sec2Q
(3) 1+ cot2Q - Cosec2Q​

Answer 1

Answer:

To prove :

sin^2Q+cos^2Q=1

we know sinQ=Perpendicular/Hypotenuse

and cosQ=Base/Hypotenuse

therefore,p^2/h^2+b^2/h^2=p^2+b^2/h^2

h^2/h^2=1.

similarly all we can do