Question

at given temperature and pressure 20 ml of gas diffuses through a porous membrane in 5 seconds calculate the volume of carbon dioxide which diffuses in 10 seconds if the vapour density of the gas is 11

Answer 1

The amount of carbon dioxide that will pass through the membrane in 10 sec will be 28.28 ml

Explanation :

We know that ,

molecular weight = 2 x vapor density

=> M₁ = 2 x 11 = 22

Molecular weight of CO₂ , M₂ = 44

The rate of diffusion is inversely proportional to square root of molecular weight,

r ∝ 1/√M

r₁/r₂ = √(M₂/M₁)

But rate of diffusion is defined as the ratio of volume and time,

=> (V₁/t₁)/(V₂/t₂) = √(M₂/M₁)

=> (20/5)/(V₂/10) = √(44/22)

=> 40/V₂ = √2 = 1.414

=> V₂ = 40/1.414 = 28.28 ml

Hence the amount of carbon dioxide that will pass through the membrane in 10 sec will be 28.28 ml