Question

At higher concentration of naoh the order of cannizzaro reaction is

Answer 1

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♦♦Cannizzaro first accomplished this transformation in 1853, when he obtained benzyl alcohol and potassium benzoate from the treatment of benzaldehyde with potash (potassium carbonate).

♦♦ More typically, the reaction would be conducted with sodium hydroxide or potassium hydroxide, giving the sodium or potassium carboxylate salt of the carboxylic-acid product:

[2 C6H5CHO + KOH → C6H5CH2OH + C6H5COOK]

♦♦The process is a redox reaction involving transfer of a hydride from one substrate molecule to the other: one aldehyde is oxidized to form the acid, the other is reduced to form the alcohol.