Math, asked by anupamasahoo9696, 1 month ago

At his first game a person loses 1/4 of his money, at the second 1/5 of the remainder, at the third 4/5 of the rest;what traction of his original money has he left?​

Answers

Answered by debanshubhattacharyy
2

Answer:

3/25

Step-by-step explanation:

let at first he had 100 rupees only

then first time he losses=100*1/4=25rupees

now money left=100-25=75

then second time he losses=75*1/5=15rupees

now money left =75-15=60rupees

for the last time he losses=60*4/5=48rupees

now total money left=60-48=12rupees

now the fraction of his left money by the original money=12/100=3/25 Answer

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