Question

At how many points the graph of polynomial f(x)=3-2x-x^2 cut x axis

Answer 1

Answer:

number of values of X for which f(x)=0,,will be the number of points where function cuts X axis.

\begin{gathered}f(x) = 3 - 2x - {x}^{2} \\ 3 - 2x - {x }^{2} = 0 \\ {x}^{2} -2x - 3 = 0 \\ {x}^{2} - 2x + 1 = 4 \\ (x - 1) {}^{2} = 4 \\ x = - 3 \\ x = 5 \\ \end{gathered}

f(x)=3−2x−x

2

3−2x−x

2

=0

x

2

−2x−3=0

x

2

−2x+1=4

(x−1)

2

=4

x=−3

x=5