At how many points the graph of polynomial
Cut x axis
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At two points it meets x axis
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-x^2 - 2x+3 = 0
-x^2 -3x+x +3=0
-x(X+3)+1(X+3) =0
(X+3)(-x+1) =0
(X+3) =0 OR (-X+1)=0
X= -3 OR -X = -1
X= -3 OR X = 1
This is your answer.....
-x^2 -3x+x +3=0
-x(X+3)+1(X+3) =0
(X+3)(-x+1) =0
(X+3) =0 OR (-X+1)=0
X= -3 OR -X = -1
X= -3 OR X = 1
This is your answer.....
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