At how much distance must an object placed from a concave mirror of focal length 15cm so that its 5 times real image is formed. Also find out the position of image.
Answers
Answered by
0
Answer:
I don't know this answer is right or wrong
Step-by-step explanation:
According to the question:
Focal length, f=−1.5 m (Since it is a concave mirror)
Object distance, u=−40 cm=−0.4 m (Since 1 m=100 cm)
By mirror formula:
v
1
+
u
1
=
f
1
[4pt]
⇒
v
1
+
−0.4 m
1
=
−1.5 m
1
[4pt]
⇒
v
1
=
0.4 m
1
−
1.5 m
1
[4pt]
⇒
v
1
=
4 m
10
−
15 m
10
[4pt]
⇒
v
1
=
2 m
5
−
3 m
2
[4pt]
⇒
v
1
=
6 m
15−4
[4pt]
⇒
v
1
=
6 m
11
[4pt]
⇒v=0.5454 m=54.54 cm
Since v=54.54 cm which is positive, hence image is behind the mirror.
The image is formed at the distance of 54.54 cm behind the mirror and is virtual and erect.
Similar questions