Chemistry, asked by riteshsheoran1394, 1 year ago

At infinite dilution the percentage ionisation for both strong and weak electrolytes is

Answers

Answered by 13nginx
1

for strong electrolyte 100% ionization

for weak electrolyte 85% ionization

Answered by mindfulmaisel
4

At the ‘infinite dilution’, the percentage ionization for both ‘strong and weak electrolytes’ is 100%.

Explanation:

The Ostwald’s dilution law defines about the law of applying the mass action to the weak electrolytes of the solution. It can be expressed as follows,

\mathrm{K}_{\mathrm{a}}=\frac{(C \propto)(C \propto)}{C(1-\propto)}=\frac{C \propto ^{2}}{1-\propto }

Here, Ka represents the ionization constant or dissociation constant of the given acid.  

represents the degree of dissociation.

At constant temperature, the degree of dissociation might be formulated as follows,

\propto=\frac{\lambda_{v}}{\lambda_{i n fini t y}}

So according to Ostwald’s dilution law, the ionization degree is directly proportional to the dilution. Hence, the percentage is 100%.  

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