AT is a tangent to a circle with centre O at A. AT=12cm,OT=13cm find the diameter of the circle
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Answer:
10
Step-by-step explanation:
OT will be hypotenuse
so OT^2 = AT^2 +OA^2
13^2= 12^2+OA^2
OA^2= 169-144=25
OA =5
so diameter = 2*OA = 2*5=10
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