Math, asked by username84, 10 months ago

At LaMar’s birthday party, his parents served slices of plain, sausage, or pepperoni pizza. They also served cups of milk, orange juice, apple juice, or lemonade. If each guest at the party chose one slice of pizza and one type of drink, how many different combinations were possible?​

Answers

Answered by tardymanchester
6

Answer : 12 different combinations were possible.

Step-by-step explanation:

Given: At LaMar’s birthday party, his parents served slices of plain, sausage, or pepperoni pizza.

i.e. The number of types of pizza = 3

They also served cups of milk, orange juice, apple juice, or lemonade.

i.e. The number of  types of drinks = 4

Now, if each guest at the party chose one slice of pizza and one type of drink, then the number of different possible combinations are :

\sf {\implies}\:3\times4=12

Hence, there were 12 different combinations .

Answered by DeviIQueen
3

Answer : 12 different combinations were possible.

Step-by-step explanation:

Given: At LaMar’s birthday party, his parents served slices of plain, sausage, or pepperoni pizza.

i.e. The number of types of pizza = 3

They also served cups of milk, orange juice, apple juice, or lemonade.

i.e. The number of types of drinks = 4

Now, if each guest at the party chose one slice of pizza and one type of drink, then the number of different possible combinations are :

\sf {\implies}\:3\times4=12⟹3×4=12

Hence, there were 12 different combinations .

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