Question

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please answer this question

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Answer 1

Answer:

23000 thousands rupees

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Answer 2

Answer:

Rs. 151200

Step-by-step explanation:

Given :

• In Mr. Gupta's money, 1/4 for son, 1/3 for daughter and remaining for wife
• Wife has Rs 63000

To find :

Money Mr. Gupta had

Solution :

We know that, counting the part total will bring to 1

So, As son part is 1/4 and daughter's is 1/3, Let wife's part be w

So,

$\implies \mathrm{\dfrac{1}{4} + \dfrac{1}{3} + w = 1 }$

$\implies \mathrm{\dfrac{7}{12} + w = 1 }$

$\implies \mathrm{w = 1 - \dfrac{7}{12}}$

$\implies \mathrm{w = \dfrac{5}{12}}$

So, wife's part is 5/12

Now it is given that wife has Rs 63000. That means 5/12 part of her husband has is Rs 63000

Let the money with Mr. Gupta be x

So,

$\implies \mathrm{\dfrac{5x}{12} = 63000}$

$\implies \mathrm{x = \dfrac{63000 \times 12}{5}}$

$\implies \mathrm{x = 12600 \times 12}$

$\implies \mathrm{x = 151200}$

$\boxed{\text{Thus, the money Mr.Gupta had was {\large{\textbf{Rs.151200}}}}}$

Hope it helps!!