❖@ Moderators
❖@ Brainly Stars
❖@ Best Users
An object 5 cm in size is placed at 12 CM in front of a concave mirror of radius of curvature of 20 CM at what distance from the mirror should a screen be placed in order to obtain a sharp image? find the nature and size of the L.
Don't dare for Spam
Answers
Answer:
☞ Nature of image:
- Real
- Inverted
- Enlarged
☞ Size of image = - 25 cm
Step-by-step explanation:
★ Given:
- Object size = 5 cm
- Concave mirror
- Object-mirror distance = u = - 12 cm
- Radius of curvature = R = 20 cm
★ To find:
Nature and size of image
★ Solution:
First let's find the focal length (f)
R = 2f
⇒ f = R/2
⇒ f = 20/2
⇒ f = 10 cm
Hence, Focal length = -10 cm
(Negative sign because it is a concave mirror)
Applying mirror formula,
Taking LCM and solving,
So, the screen must be placed at a distance of 60 cm in front of the mirror to obtain a sharp image.
Now, let's find it's magnification.
Magnification is in negative. So, the image is real and inverted.
Modulus of magnification = |m| = 5
5 > 1
So, the image is enlarged.
∴ Nature of image:
- Real
- Inverted
- Enlarged
Also,
Some TIPS to find nature of image from magnification:
⭐ If magnification is positive, image is virtual and erect
⭐ If magnification is negative, image is real and inverted
⭐ If modulus of magnification is greater than 1, then the image is enlarged
⭐ If modulus of magnification is lesser than 1, then the image is diminished
⭐ If modulus of magnification = 1, image is same size of the object.