Math, asked by heer588110, 1 month ago

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Solve this -
Bhagwanti inherited rupees 12000. She invested part of it as 10% and rest at 12% .Her annual income from these investment is rupees 1280. How much did she invest at each rate.
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Answers

Answered by kartiksharma0711
1

Step-by-step explanation:

Total money =12000Rs.

First investment =x Rs.

Second investment =(12000−x)Rs.

First income =

100

10

×x=

10

x

Second income =

100

12

(12000−x)

So

100

10x

+

100

12

(12000−x)=1280

⇒10x+144000−12x=128000

⇒144000−128000=2x

⇒x=

2

16000

=8000

12000−x=4000

Investments are 8000 & 4000 Rs.

Answered by priyanshuawas011
0

Answer:

Let

R

s

.

x

was invested @10% and

R

s

.

(

12000

x

)

was invested @12%.

So by the problem

x

×

10

%

+

(

12000

x

)

×

12

%

=

1280

12000

×

12

%

x

×

2

%

=

1280

12000

×

12

x

×

2

=

128000

2

x

=

144000

128000

=

16000

x

=

8000

So

R

s

.8000

was invested @10% and

R

s

.

(

12000

8000

)

=

R

s

.4000

was invested @12%

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