at mouth tap the area of cross section is 2.0. cm square and the speed of water is 3 m/s . The area of cross section of the water column 80 cm below the tap os use g = 10 m/s square
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Step-by-step explanation:
Given
at mouth tap the area of cross section is 2.0. cm square and the speed of water is 3 m/s . The area of cross section of the water column 80 cm
Let velocity of water 80 cm below the tap be V
We know that from Equation of motion
v^2 = u^2 + 2as or 2gh
so v^2 = 3^2 + 2 x 10 x 80/100
So v^2 = 9 + 16
so v^2 = 25
So v = 5 m/s
Now from equation of Continuity we get
A1V1 = A2V2
2 x 3 = 5 x A2
Or A2 = 6/5 sq cm
Or A2 = 1.2 sq cm
Reference link will be
https://brainly.in/question/1827471
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