Question

at N.T.P. the volume of a gas is found to be 273 ml.What will be the volume of this gas at 600 mm hg and 273℃

Answer 1

If wrong let me know

Answer 2

Answer: 644 ml

Explanation:

Normal condition of temperature (NTP) is 293 K and atmospheric pressure is 1 atm respectively.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = pressure of gas at NTP = 1 atm = 760 mmHg

$P_2$ = pressure of gas = 600 mm Hg

$V_1$ =  Volume of gas at NTP = 273 ml

$V_2$ = volume of gas = ?

$T_1$ = temperature of gas at NTP = $293K$

$T_2$ = temperature of gas = $273^0C=(273+273)K=546K$

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{760mmHg\times 273ml}{293K}=\frac{600mmHg\times V_2}{546K}$

$V_2=644ml$

Therefore, the volume of this gas at 600 mm Hg and 273℃ is 644 ml.