Question

At normal temperature and pressure 0.24 gm
volatile substance produces 43 ml. Vapour. Then
the vapour density of substance will be -
(Density of hydrogen = 0.000089gm/ml)
[AIPMT-96]
(1) 95.39
(2) 5.993
(3) 95.93
(4) 62.7
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Answer 1

43mL gives 0.24g

, Then 22400ml (1mole) will give 0.24*22400/43 which is approximately 125g

So we know vapur density *2= molecular weight

So vapour density =125/2=62.5

Or 0.24/43*0.000089=62.7