At ntp 5.6 litre of gas weight 8g. Its vapour density is
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Answered by
4
At NTP the volume of gas = 22.4 L
Given volume of gas = 5.6 L
Therefore no of mole =
no of mole = 1/4 = 0.25 moles
vapor density = 2 * molecular weight
molecular weight = = 0.25 * 8 = 2
vapour density = 2*2=4
Given volume of gas = 5.6 L
Therefore no of mole =
no of mole = 1/4 = 0.25 moles
vapor density = 2 * molecular weight
molecular weight = = 0.25 * 8 = 2
vapour density = 2*2=4
Answered by
15
1 mol of any gas at STP acquires 22.4 L
Moles of gas in 5.6 L is = 5.6 / 22.4 = 0.25
Molecular weight = w / n = 8 g / 0.25 mol = 32 g/mol
Vapour density = Molecular weight / 2
= 32 / 2
= 16
Vapour density of gas is 16
Moles of gas in 5.6 L is = 5.6 / 22.4 = 0.25
Molecular weight = w / n = 8 g / 0.25 mol = 32 g/mol
Vapour density = Molecular weight / 2
= 32 / 2
= 16
Vapour density of gas is 16
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