Question

At NTP, density of mixture of N2 and O, is 1.3 g/L. The partial pressure of Oz in mixture will be:
0.28 atm
0.56 atm
0.44 atm
0.72 atm​

Answer 1

Answer:

Density =

Volume

Weight

At S.T.P., 1.3=

22.4

Weight

⇒Weight=22.4×1.3=29.12g

Weight

mixture

=29.12=Weight

O

2

+Weight

N

2

=n

O

2

M

O

2

+n

N

2

M

N

2

=x×32+(1−x)×28

x=0.28 mole

(where n represents the molecular weight and x represents mole fraction)

Moles of O

2

=0.28

At S.T.P., pressure =1 atm

Partial pressure of O

2

=

n

total

n

O

2

×pressure=

1

0.28

×1=0.28 atm.

Answer 2

Answer:

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