Question

At NTP what volume of NH3 is occupied by 17 g NH3

Answer 1

Roughly 0.0323 metres cubed at first calculation assuming the ammonia acts as an ideal gas.

The calculation: 24.5g/17 grams per mol gives 1.441 moles of ammonia. 1.441 x 22.4 = 32.3 however since we're only dealing with moles and not kmols, the gas only occupies 0.0323 metres cubed. Tip: 1kmol of ideal gas occupies roughly 22.4 metres cubed at STP.

Answer 2

first we will calculate the mole of NH3

mole of NH3= 17/17=1mole (given weight/ molicular weight).

volume of 1 mole of gas at NTP =22.4L.

So volume of 1mole of NH3 at NTP=22.4L