Question

at particular concentration, Half-Life of the reaction is 1000minutes .When the concentration of the reactantbecomes double half life becomes ,25 minutes, then what will be the order of the 4

Answer 1

Answer : The order of reaction is, 6

Explanation :

Formula used :

$n=\frac{\log(\frac{t_{1/2(1)}}{t_{1/2(2)}})}{\log(\frac{a_2}{a_1})}+1$

where,

n = order of reaction = ?

$t_{1/2}_{1}$ = half-life of a substance at initial concentration = 1000 min

$t_{1/2}_{2}$ = half-life of a substance at final concentration = 25 min

$a_{1}$ = initial concentration = X

$a_{2}$ = initial concentration = 2X

Now put all the given values in the above formula, we get the order of reaction.

$n=\frac{\log{(\frac{1000min}{25min})}}{\log{(\frac{2X}{X})}}+1$

$n=6$

Therefore, the order of reaction is, 6