Question

At present, Aditi is twice as old as her son. After six yearher age and her's son's age will be in the ratio 23: 13. Find the present age of aditi and her son respectively.​

Answer 1

Let Aditi's son be x years old

son be x years oldAditi will be 2x years old

son be x years oldAditi will be 2x years old12years hence,

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138=> 26x-23x = 138-78

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138=> 26x-23x = 138-78=> 3x = 60

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138=> 26x-23x = 138-78=> 3x = 60=> x = 60/3

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138=> 26x-23x = 138-78=> 3x = 60=> x = 60/3=> x = 20

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138=> 26x-23x = 138-78=> 3x = 60=> x = 60/3=> x = 20 Therefore, Aditi's age = 2 * 20 = 40 years

son be x years oldAditi will be 2x years old12years hence,=> 2x + 6 / x + 6 = 23/13=> (2x+6) * 13 = (x+6) * 23=> 26x+78 = 23x+138=> 26x-23x = 138-78=> 3x = 60=> x = 60/3=> x = 20 Therefore, Aditi's age = 2 * 20 = 40 years Her son's age = 20 years

Answer 2

Answer:

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