Math, asked by vamsib6667, 11 months ago

At present, age of a father is twice that of his elder son. Ten years hence, age of the father will be 3 times that of the younger son. If the different in ages of the two sons is 15 years, the present age of the father is:

Answers

Answered by ramveerkumar30
2
let the age of elder son be X.
age of father be 2 X .
age of younger son be X-15.
ATQ
after ten years father will be three times his younger son.
so, after ten years father age will be 2X+10 year and younger son age would be X-15+10 or X+5 year.
so,3(X+5)=2X +10
or, 3X+15=2X+10
or,X=25
age of elder son is 25 years.
age of father is 25*2=50 years.
age of younger son is 25-15=10years.

Answered by alibarmawer
0

Answer:

let the age of elder son be X.

age of father be 2 X .

age of younger son be X-15.

ATQ

after ten years father will be three times his younger son.

so, after ten years father age will be 2X+10 year and younger son age would be X-15+10 or X+5 year.

so,3(X+5)=2X +10

or, 3X+15=2X+10

or,X=25

age of elder son is 25 years.

age of father is 25*2=50 years.

age of younger son is 25-15=10years.

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