Question

at present age of father is twice the sum of the present age of his two children 20 year hence the age of the father will be the equal to the sum of the age of those two children find the present age of the father​

Answer 1

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• Present age of father is twice the sum of the present age of his two children

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• 20 year hence the age of the father will be the equal to the sum of the age of those two children

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• Present age of the father

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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• Let the present age of father be "x"

• Let the present of 1st children be "y"

• Let the present age of 2nd children be "z"

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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Present age of father is twice the sum of the present age of his two children

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➨ x = 2(y + z) --------- (1)

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$\underline{\bold{\texttt{Father's age after 20 years :}}}$

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➨ x + 20

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$\underline{\bold{\texttt{1st children's age after 20 years :}}}$

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➨ y + 20

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$\underline{\bold{\texttt{2nd children's age after 20 years :}}}$

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➠ z + 20

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Also given that , affer 20 years the age of the father will be the equal to the sum of the age of those two children

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➜ y + 20 + z + 20 = x + 20

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➜ y + z + 40 = x +20

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➜ y + z = x + 20 - 40

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➜ y + z = x - 20 ------- (2)

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⟮ Putting the value of y + z from (2) to (1) ⟯

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➜ x = 2(y + z)

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➜ x = 2(x -20)

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➜ x = 2x – 40

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➜ 2x - x = 40

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➨ x = 40

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• Hence, father’s present age is 40 years

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Answer 2

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

$\:\:$

$\large{\green{\underline \bold{\tt{Given :-}}}}$

$\:\:$

• Present age of father is twice the sum of the present age of his two children

$\:\:$

• 20 year hence the age of the father will be the equal to the sum of the age of those two children

$\:\:$

$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

$\:\:$

• Present age of the father

$\:\:$

$\large{\orange{\underline{\tt{Solution :-}}}}$

$\:\:$

Let the present age of father be "x"

Let the present of 1st children be "y"

Let the present age of 2nd children be "z"

$\:\:$

$\purple{\underline \bold{According \: to \: the \ question :}}$

$\:\:$

Present age of father is twice the sum of the present age of his two children

$\:\:$

➨ x = 2(y + z) --------- (1)

$\:\:$

$\underline{\bold{\texttt{Father's age after 20 years :}}}$

$\:\:$

➨ x + 20

$\:\:$

$\underline{\bold{\texttt{1st children's age after 20 years :}}}$

$\:\:$

➨ y + 20

$\:\:$

$\underline{\bold{\texttt{2nd children's age after 20 years :}}}$

$\:\:$

➠ z + 20

$\:\:$

Also given that , affer 20 years the age of the father will be the equal to the sum of the age of those two children

$\:\:$

➜ y + 20 + z + 20 = x + 20

$\:\:$

➜ y + z + 40 = x +20

$\:\:$

➜ y + z = x + 20 - 40

$\:\:$

➜ y + z = x - 20 ------- (2)

$\:\:$

⟮ Putting the value of y + z from (2) to (1) ⟯

$\:\:$

➜ x = 2(y + z)

$\:\:$

➜ x = 2(x -20)

$\:\:$

➜ x = 2x – 40

$\:\:$

➜ 2x - x = 40

$\:\:$

➨ x = 40

$\:\:$

Hence, father’s present age is 40 years

$\:\:$

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