Math, asked by GouthamGS1373, 10 months ago

At present ages of a father and his son are in the ratio 7 :3and they will be in the ratio 2 ratio 1 after 10 year then the present age of father (in year )is

Answers

Answered by agamdeep34
1

Answer:

present age of father=7×

present age of son=3×

AFTER 10 YEARS...

present age of father=(7×+10)

present age of son =(3×+10)

ACCORDING TO STATEMENT.

7×+10/3×+10=2/1

1(7×+10)=2(3×+10)

7×+10=6×+20

7×-6×=20-10

×=10

PRESENT AGE OF FATHER=7×=7×10=70

PRESENT AGE OF SON=3×=3×10=30

Step-by-step explanation:

MARK AS BRAINLISH PLZZZ.

Similar questions