Question

At present asha's age (in years) is 2 more than square of her daughter nisha's age. When nisha grows to her mother's present age, asha's age would be one year less than 10 times the present age of nisha. Find the present ages of both.​

Answer 1

Step-by-step explanation:

Let Nisha age be x:

Present age;

Asha=x²+2

Future according to question;

Nisha=x²+2

Equation;

x²+2=10(x²+2+1)

x²+2=10x²+30

28=9x²

Answer 2

Answer:

Let, Nisha’s present age be = x year

Therefore, according to the first condition, Asha's present age = x2 + 2

Nisha grows to her mother's present age after [(x² + 2) – x] years.

Then, Asha's age will become (x² + 2) + [(x² + 2) –x] years.

• According to the question :

⟹ (x² + 2) + [(x² + 2) – x] = 10x – 1

⟹ 2x² – x + 4 = 10x – 1

⟹ 2x² – 11x + 5 = 0

⟹ 2x² – 10x – x + 5= 0

⟹ 2x (x – 5) –1(x – 5) = 0

⟹ (x – 5) (2x – 1) = 0

⟹ (x – 5) = 0 or (2x – 1) = 0

⟹ x = 5 or 1/2

Ignoring x = 1/2 because then Asha’s age = x² + 2 = which is not possible.

Hence, Present Age of Nisha = 5 years

And Present Age of Asha = x² + 2 = (5)² + 2 = 25 + 2 = 27 years