Question

At present Asha’s age (in years) is 2 more than the square of her daughter Nisha’s age. When Nisha grows to her

mother’s present age, Asha’s age would be one year less than 10 times the present age to Nisha. Find the present

ages of both Asha and Nish​

Answer 1

Step-by-step explanation:

Suppose present age of Nisha = x years

-> Asha's age is 2 more than the square of nisha's age

Therefore, Asha's age = x^2 + 2

-> When Nisha grows as much as Asha

i.e. Nisha's age will be x^2 +2

-> Asha's age would be 1year less than 10 times nisha's present age

i.e. Asha's age = 10x - 1