At present Asha’s age (in years ) is 2 more than the square of her daughter Nisha’s
age . When Nisha grows to her mother’s present age , Asha’s age would be one year less
than 10 times the present age of Nisha. Find the present ages of both Asha and Nisha .
Answers
Answered by
12
hello....
Present age of Asha is 2+x2 yrs
Present age of Nisha is x yrs.
difference in asha 's and nisha 's ages =x2 + 2 - x
so , after x2 + 2 - x years....nisha will grow to asha 's age
now to calculate asha 's age when nisha 's age will be x2 + 2 , add x2 +2 to x2 + 2 - x ...!!
i.e.
x2 + 2 + x2 + 2 - x = 10x -1
2x2 + 4 - x = 10x - 1
2x2 - 11x + 5 = 0
2x2 - 10x - 1x + 5 = 0
2x ( x -5 ) -1 ( x - 5) = 0
(2x - 1) ( x - 5 ) = 0
so , x = 5 years
asha 's age = x2 + 2 = 27
thank you...
☺
Present age of Asha is 2+x2 yrs
Present age of Nisha is x yrs.
difference in asha 's and nisha 's ages =x2 + 2 - x
so , after x2 + 2 - x years....nisha will grow to asha 's age
now to calculate asha 's age when nisha 's age will be x2 + 2 , add x2 +2 to x2 + 2 - x ...!!
i.e.
x2 + 2 + x2 + 2 - x = 10x -1
2x2 + 4 - x = 10x - 1
2x2 - 11x + 5 = 0
2x2 - 10x - 1x + 5 = 0
2x ( x -5 ) -1 ( x - 5) = 0
(2x - 1) ( x - 5 ) = 0
so , x = 5 years
asha 's age = x2 + 2 = 27
thank you...
☺
VivekGupta4040:
Thanx
Answered by
2
Answer:
Let, Nisha’s present age be = x year
Therefore, according to the first condition, Asha's present age = x2 + 2
Nisha grows to her mother's present age after [(x² + 2) – x] years.
Then, Asha's age will become (x² + 2) + [(x² + 2) –x] years.
• According to the question :
⟹ (x² + 2) + [(x² + 2) – x] = 10x – 1
⟹ 2x² – x + 4 = 10x – 1
⟹ 2x² – 11x + 5 = 0
⟹ 2x² – 10x – x + 5= 0
⟹ 2x (x – 5) –1(x – 5) = 0
⟹ (x – 5) (2x – 1) = 0
⟹ (x – 5) = 0 or (2x – 1) = 0
⟹ x = 5 or 1/2
Ignoring x = 1/2 because then Asha’s age = x² + 2 = which is not possible.
Hence, Present Age of Nisha = 5 years
And Present Age of Asha = x² + 2 = (5)² + 2 = 25 + 2 = 27 years
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