Question

At present asha's age is 2 more than the square of a daughter nisha's age when she goes to her mother's presented asha's age would be one year less than 10 times the present age of nisha find the present ages of both

Answer 1

Heya...

Here's your answer.........

Let Nisha's age is x years

Aisha's age = (x² + 2) years

Now, A/C to question , when Nisha grows to her mother present age .means Nisha's grows = Aisha's present age - Nisha's present age = x² + 2 - x

Then, this time Aisha's age = Aisha's present age + growing time = x² + 2 + x² + 2 - x = 2x² - x + 4

Now, question said , Aisha's age = 10× times of Nisha's age -1

2x² - x + 4 = 10x -1

2x² - 11x + 5 = 0

2x² -10x - x + 5 = 0

x = 5 and 1/2 x ≠ 1/2 because age doesn't in moths

Hence , Nisha's present age = 5 years

Aisha's present age = (5)² + 2 = 27 years

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✨✨✨✨BY BeWaFa ✨✨✨

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Answer 2

Answer:

Let, Nisha’s present age be = x year

Therefore, according to the first condition, Asha's present age = x2 + 2

Nisha grows to her mother's present age after [(x² + 2) – x] years.

Then, Asha's age will become (x² + 2) + [(x² + 2) –x] years.

• According to the question :

⟹ (x² + 2) + [(x² + 2) – x] = 10x – 1

⟹ 2x² – x + 4 = 10x – 1

⟹ 2x² – 11x + 5 = 0

⟹ 2x² – 10x – x + 5= 0

⟹ 2x (x – 5) –1(x – 5) = 0

⟹ (x – 5) (2x – 1) = 0

⟹ (x – 5) = 0 or (2x – 1) = 0

⟹ x = 5 or 1/2

Ignoring x = 1/2 because then Asha’s age = x² + 2 = which is not possible.

Hence, Present Age of Nisha = 5 years

And Present Age of Asha = x² + 2 = (5)² + 2 = 25 + 2 = 27 years