at present father age is thrice than that of his son 6 years back his age was four times than that of the son what will be the ratio of their ages after 6 years solve the problem
Answers
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Let the son be x
Father = 3x
STEP 1: Find their age 6 years ago:
Son = x - 6
Father = 3x - 6
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STEP 2 : Form equation and solve for x:
6 years ago, father was 4 times that of the son:
3x - 6 = 4( x - 6)
3x - 6 = 4x - 24
4x - 3x = 24 - 6
x = 18
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STEP 3: Find their present age:
Son = x = 18 years old
Father = 3x = 3(18) = 54 years old
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STEP 4: Find their age 6 years later:
Son = x + 6 = 18 + 6 = 24 years old
Father = 3x + 6 = 54 + 6 = 60 years old
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STEP 5: Find their ratio:
Father : Son = 60 : 24
Simplify:
Father : Son = 5 : 2
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Answer: Their ratio will be 5 : 2
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