Math, asked by uvgagan, 1 year ago

at present meena is eight times her daughter's age eight years from now the ratio of the ages of meena and her daughter will be 10:3 respectively what is meena's present age?

Answers

Answered by Nayantripathi
5
Hope this is the brainliest answer
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Answered by throwdolbeau
2

Answer:

Meena's age = 32 years

Step-by-step explanation:

Let Meena's daughter present age be x years

And Meena's age is 8 time that of the daughter's age

⇒ Meena's age is 8x years

After 8 years from now :

\frac{\text{Meena age}}{\text{Daughter age}}=\frac{10}{3}\\\\\implies \frac{8x+8}{x+8}=\frac{10}{3}\\\\\implies 24x+24=10x+80\\\implies 14x=56 \\\implies x = 4

Therefore, Meena's age = 8x

                                         = 8 × 4

                                         = 32 years

       

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