Question

at present monas age is 2more than the square of her daughtwr charvies frows to her mothers present age mona age would be one year less than 10 times the present age of charvi find the present ages ofboth mona and charvi

Answer 1

Let Mona's age be M and her daughter's age be C

According to question

M = 2 + C^2

also

M = 10C- 1

Solving the above two equations

10C - 1 = 2 + C^2
 C^2 - 10C +3 = 0
C( C-10) = -3
 Thus C= 7
so

M = 2 + (7)^2\
M = 51

Thus mona's age is 51 years and her daughter's age is 7 years

Answer 2

Let Mona'S [mother's ] age be X

Daughter's age be Y

So according to given:

X=2+Y²----------1

X=10Y-1----------2

solving equation 1 and 2 we get

10Y-1=2+Y² 

Y²-10Y+3=0

Y(Y-10)=-3

Y-10=-3

Y=7

So X=2+7²

=2+49=51 years

∴Mothers age is 51years and her daughters age is 7