Question

At present one number is seven times the other If their difference is 18 , find the number

Answer 1

Given -

• one number is seven times the other.

• Their difference is 18.

To find -

• Find the number.

Solution -

Here, we are given with statement only and we need to make a linear equation out of it, and then solve the problem. First we will take the no: as x and then second as 7x, then by transpose method, we will solve it further.

So-

Let the number be termed as x

One is seven times the other number = 7x

Difference is of 18

On substituting the values -

$7x-x=18\\\\6x=18\\\\x=\frac{18}{6} \\\\x=3$

Now -

• First number = 3

• Second number = 7x = 7 × 3 = 21

Verification -

21 - 3 = 18

18 = 18

The first and second number are 3 and 21

______________________________________________

Answer 2

Answer:

QUESTION:-

At present one number is seven times the other If their difference is 18 , find the number:-

SOLUTION:-

Let the number be x and let the other number be (x × 7).

According to the question:-

=> 7x - x = 18

=> 6x = 18

=> x = 18

6

=> x = 3

Thus, one of the number is 3.

Step-by-step explanation:

CHECK:-

One of the number = 3

Other number = ( 3 × 7)

Other number = 21

Difference between the number = (21 - 3)

Difference between the number = 18

Hence, the numbers are 3 and 21.

HOPE IT HELPS YOU! THANKS FOR ASKING...